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Lady_Fox [76]
3 years ago
15

M = 2/3, B = -5 M = -5, b = 3/2 M = 2, b = -6 M = -5, b= 2

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer: m = 3/2, b = -5

Step-by-step explanation:

When we input these values into slope-intercept form y = mx + b, then we get y = 3/2x -5. When trying out different x values, we get the same points that are on the line such as (2, -2) also the y-intercept is -5, so we know it is a true statement and that the slope 3/2 and y-intercept -5 are the only correct answers for this line.

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trasher [3.6K]
\bf \textit{Double Angle Identities}&#10;\\ \quad \\&#10;sin(2\theta)=2sin(\theta)cos(\theta)&#10;\\ \quad \\&#10;cos(2\theta)=&#10;\begin{cases}&#10;cos^2(\theta)-sin^2(\theta)\\&#10;1-2sin^2(\theta)\\&#10;\boxed{2cos^2(\theta)-1}&#10;\end{cases}&#10;\\ \quad \\&#10;tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\&#10;-------------------------------\\\\&#10;

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now, bear in mind, the square root gives us +/- versions, so, which is it? well, we know the angle is in the range of "<span>0 ≤ θ < π/2", that simply means the 1st quadrant, so, we'll use the positive one then

</span>\bf cos(\theta)=\cfrac{\sqrt{11}}{\sqrt{12}}\implies cos(\theta)=\cfrac{\sqrt{11}}{2\sqrt{3}}&#10;\\\\\\&#10;\textit{now, let's rationalize the denominator}&#10;\\\\\\&#10;\cfrac{\sqrt{11}}{2\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{11}\cdot \sqrt{3}}{2\sqrt{3^2}}\implies \cfrac{\sqrt{11\cdot 33}}{2\cdot 3}\implies \boxed{\cfrac{\sqrt{33}}{6}}<span>
</span>
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