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spayn [35]
3 years ago
12

Who can help me in geometry work? JUST HAVE TWO ASSIGNMENTS‼️‼️‼️​

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

Where are the assignments?

Step-by-step explanation:

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Describe the TRANSFORMATIONS below. * f(x)= (x-6)²+4
Brilliant_brown [7]

Answer:

Move right 6 units and up 4 units

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

<em>a</em> = vertical stretch/shrink

<em>b</em> = horizontal stretch/shrink

<em>h</em> = horizontal movement left/right

<em>k</em> = vertical movement up/down

5 0
3 years ago
Wat is 74 increased by 3 times y
Lena [83]
That means i think
74+3y
5 0
4 years ago
Find the work done by the force field F(x,y,z)=6xi+6yj+6k on a particle that moves along the helix r(t)=3 cos(t)i+3sin(t)j+2 tk,
kramer

Answer:

the work done by the force field = 24 π

Step-by-step explanation:

From the information given:

r(t) = 3 cos (t)i + 3 sin (t) j + 2 tk

= xi + yj + zk

∴

x = 3 cos (t)

y =  3 sin (t)

z = 2t

dr = (-3 sin (t)i + 3 cos (t) j + 2 k ) dt

Also F(x,y,z) = 6xi + 6yj + 6k

∴  F(t) = 18 cos (t) i + 18 sin (t) j +6 k

Workdone = 0 to 2π ∫ F(t) dr

\mathbf{= \int \limits ^{2 \pi} _{0} (18 cos (t) i + 18 sin (t) j +6k)(-3 sin (t)i+3cos (t) j +2k)\ dt}

\mathbf{= \int \limits ^{2 \pi} _{0} (-54 \ cos (t).sin(t) + 54 \ sin (t).cos (t) + 12 )    \ dt}

\mathbf{= \int \limits ^{2 \pi} _{0} 12    \ dt}

\mathbf{= 12 \times 2 \pi}

= 24 π

3 0
4 years ago
Using a graphing calculator (desmos.com) graph and screenshot the following graphs:
Setler [38]
The graphs are attached.  Each graph is transformed by a horizontal translation or vertical translation or a reflection.

4 0
3 years ago
Plz help me with this
erica [24]

Answer:

the answer is b

Step-by-step explanation:

b is 9 thank you

3 0
3 years ago
Read 2 more answers
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