The answer is:103
7 goes into 7 once, then you subtract 7 from 7 which is zero. Bring down the 2 and it goes in 0 times, so you put zero on top and subtract, bring down the 1 then you get 21, which goes in 3 times.
Hope it helps!!
Answer:
The graph of the function opens downwards.
Step-by-step explanation:
The graph opens upward if the coefficient of x^2 is higher than 0.
But, the coefficient of x^2 (-3) is less than 0.
So the graph of the function opens downwards.
Slope: 0
Y-intercept: 5
The answer is 0,5
I hope this helps.
Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
