Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
3025
Step-by-step explanation:
let's look at it in this concept.
For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.
LCM of 11 and 5=55
therefore the number is 55x, where x is a positive integer.
it is a said that the number is a perfect square
therefore the square root of 55x must be an integer.

the smallest value of x to make 55x a perfect square is....

Therefore the number is.... .

<em>sweet</em><em> </em><em>right</em>
<h2>
<u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u></h2>
Integers are positive and negative whole numbers no fractions or decimals.
Real numbers do have fractions and decimals that integers do not.
Answer:
I think its b
Step-by-step explanation:
Answer:
74.7
Step-by-step explanation: