Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer:
A
Step-by-step explanation:
Plate X will result in the lightest place since it's density and thickness both are less.
Answer:
x = 1/18
Step-by-step explanation:
2/3x = 12
multiply both sides by 3x
2/3x(3x) = 12(3x)
2 = 36x
x = 1/18
Answer:
Area = 1808.64 cm
Step-by-step explanation:
Circumference of a circle = 2πr
Circumference = 150.72
π = 3.14
r = radius
150.72 = 2 x 3.14 x r
150.72 = 6.28 r
r = 150.72/6.28
r = 24cm
Radius = 24
Area of a circle = πr²
Area = 3.14 x 24²
Area = 3.14 x 576
Area =1808.64 cm
F(x)=x^3+x^2-9x-9
x^2(x+1)-9(x+1)
=(x+1)(x^2-9)
=(x+1)(x+3)(x-3)
Hope that this helps
