Based on the given conditions, formulate:
Rearrange unknown terms to the left side of the equation:
Combine like terms:
Calculate the sum or difference:
Divide both sides of the equation by the coefficient of variable:
Answer: k=41/3
Answer:
![\pmb{ \pink{QUESTION�}}](https://tex.z-dn.net/?f=%20%5Cpmb%7B%20%5Cpink%7BQUESTION%EF%BF%BD%7D%7D)
Find the midsegment of the triangle which is parallel to CA.
![\pmb{ \pink{ANSWER:-}}](https://tex.z-dn.net/?f=%20%5Cpmb%7B%20%5Cpink%7BANSWER%3A-%7D%7D)
Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.
![\frak{Explanation:-}](https://tex.z-dn.net/?f=%20%20%5Cfrak%7BExplanation%3A-%7D%20)
We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.
![\implies\rm{midsegment \: EG \: parallel \: to \: CA}](https://tex.z-dn.net/?f=%5Cimplies%5Crm%7Bmidsegment%20%5C%3A%20%20EG%20%5C%3A%20parallel%20%5C%3A%20to%20%5C%3A%20%20CA%7D)
~
[ Answer ]
![\boxed{270 \ Yards^{2} }](https://tex.z-dn.net/?f=%5Cboxed%7B270%20%5C%20Yards%5E%7B2%7D%20%7D)
[ Explanation ]
- Find Area Of Rectangle That Measures 18 Feet Long And 15 Feet Wide
-----------------------------------
Area = Base · Height
Base - 15
Height - 18
- Insert Numbers Into Equation
15 · 18
15 · 18 = 270
270 ![Yards^{2}](https://tex.z-dn.net/?f=Yards%5E%7B2%7D)
![\boxed{[ \ Eclipsed \ ]}](https://tex.z-dn.net/?f=%5Cboxed%7B%5B%20%5C%20Eclipsed%20%5C%20%5D%7D)
The 4 in the first one is in the thousands place, the second one doesn't have a 4 and the 4 in the third one is in the hundreds place. Hope this helped.