Answer:
Step-by-step explanation:
<u>The first equation:</u>
<u>The second equation:</u>
<u>Convert to slope-intercept form:</u>
- x + 2y = 23 ⇒ 2y = -x + 23 ⇒ y = -1/2x + 11.5
- 2x + 3y = 39 ⇒ 3y = -2x + 39 ⇒ y = -2/3x + 13
<em>The graph is attached</em>
<u>Intersection point is (9, 7)</u>
- Adult tickets cost $9
- Child tickets cost $7
Answer: √20 is between 4.47 and 4.48
Step-by-step explanation: Square roots of numbers between perfect squares are irrational numbers. 16 and 25 are squares of 4 and 5, so the irrational number we are looking for must be about halfway between 16 and 25.
is more than 4.47 and less than 4.48
Answer:
Initial dive: - 248 (below the surface which represents '0')
Second dive: -10
Present depth -248 + -10 = -258 feet below the surface
Step-by-step explanation:
We can use negative integers to represent real-world scenarios such as in elevation and descent, bank account balances and temperatures. In this case, because a diver is descending below the surface of the water, the surface of the water represents the '0' and going down into the water would be negative integers. So, his initial dive is 248 down, or negative 248 (-248), he then dives down an additional 10 feet, or negative 10 (-10). Since the second dive is in addition to his initial dive, we add the two integers together:
-248 + -10 = -258 feet
Answer:
2fg
Step-by-step explanation:
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.