Question

Write the equation of the line passing through (-3, 4) and normal to -2x + 7y = -3. (Note: normal means perpendicular)

Answer 1

Answer:

The answer to your question is     y = -7/2x -13/2

Step-by-step explanation:

Point = (-3, 4)

Line   -2x + 7y = -3

Process

1.- Solve equation for y to find the slope of the perpendicular line

                  7y = 2x - 3

                    y = 2/7 x - 3/7

slope = 2/7

Slope of the perpendicular line = -7/2

2.- Find the equation of the new line

                   y - y1 = m(x - x1)

                   y - 4 = -7/2(x + 3)

                   y - 4 = -7/2x - 21/2

                   y = -7/2x - 21/2 + 4

                   y = -7/2x -21/2 + 8/2

3.- Result

                   y = -7/2x -13/2