If the figure is translated 4 units and 2 units down what are the coordines

How do you solve 4(8x+5)

alexandr1967 [171]

Answer:

32x+20

Step-by-step explanation:

4*8x+4*5=

32x+20

3 0

3 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago

HELP PLEASE!! I NEED HELP ASAP!

Alex73 [517]

Answer:

4. A

5. B

Step-by-step explanation:

4. I'll solve question four first:

The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.

5--3/2--2 or 8/4;simplified to 2/1 or 2.

Now use point-slope form: y-y1 = m(x-x1)

y--3 = 2(x--2): Substitute in the values of y1, m, and x1.

y+3 = 2x + 4: Distribute.

y = 2x + 1: Subtract three from both sides.

5. Do the same for question 5.

The first point is (-4, 2), the second point is (4, -1).

-1-2/4--4; -3/8.

Now use point-slope form:

y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.

y = -3/8x + 1/2

7 0

3 years ago

189 divided by 9941.4

vovikov84 [41]

The answer is 0.0190114068441065

4 0

4 years ago

5sin²α+3cos²α / 3sin²α-5cos²α = <br> if tgα=√2

fiasKO [112]

Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)

sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)

cos(α) = adjacent/hypotenuse
= 1/sqrt(3)

now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math

8 0

3 years ago