Any time the car is driving, the amount of gas is decreasing.
The only time the amount of gas can increase is the short time when
the car is parked at the gas station and gas is being poured into it.
Amanda drover towards the shop, stopped and got gas, then
drove some more. So the amount of gas decreases for a while,
then increases for a short time, then decreases again.
The middle graph is the one doing that.
Answer:
t= -1.33 recurring and -2
Step-by-step explanation:
3t²+4t+8=-6t
3t²+4t+6t+8
3t²+10t+8
This is a quadratic equation, it can be solved by using either factorisation, completing the square method or formulae method. For the purpose of this question, I would be using the formulae method.
-b±√(b²-4ac)/2a
Where a=3, b= 10 and c=8
-10±√(10²-4(3)(8))/2(3)
-10±√(100-96)/6
(-10±√4)/6
(-10±2)/6
-10+2/6 or -10-2/6
-8/6 or -12/6
-1.3333 recurring or -2
Answer:
What do I have to do?? I don't understand
I cannot do this because it wont let me look at the attachment i am sorry
Answer:
answer = 3
Step-by-step explanation:
same slope and different y-intercept would make the two lines parallel. hope this helps <3
