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Butoxors [25]
4 years ago
10

Amrita thinks of a number, she doubles it, adds 9, divides by three and then subtracts one.

Mathematics
2 answers:
FinnZ [79.3K]4 years ago
5 0

Answer:

x = 6

Step-by-step explanation:

<em>Let the number be x</em>

<u><em>Now let's make an equation for it:</em></u>

=> \frac{2x+9}{3} -1 = x

=> \frac{2x+9}{3} = x+1

<em>Multiplying both sides by 3</em>

=> 2x+9 = 3(x+1)

=> 2x+9 = 3x+3

=> 3x-2x = 9-3

=> x = 6

wariber [46]4 years ago
3 0

Answer:

I believe your answer would be 6.

Step-by-step explanation:

I have set up an equation that represents the situation.

Letting the unknown number being 'n':

\frac{2n+9}{3} -1=n

\frac{2n+9}{3} -1=n\\\\\frac{2n+9}{3}-1+1=n+1\\\\\frac{2n+9}{3}=n+1\\\\\frac{2n+9}{3}*3=3(n+1)\\\\2n+9=3n+3\\\\2n+9-9=3n+3-9\\\\2n=3n-6\\\\2n-3n=3n-3n-6\\\\-n=-6\\\\\frac{-n}{-1}=\frac{-6}{-1}\\\\  \boxed{n=6}

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See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

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First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

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Problem 2)

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Distribute and simplify:

\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}

Cancel. Hence:

\displaystyle =\frac{1}{(a-b)(a-c)}

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