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3 years ago

13

What is the probability of getting a odd number when you roll a dice

2 answers:

Alexxx [7]3 years ago

8 0

Answer:

50% (1/2)

Step-by-step explanation:

3 of the 6 sides that exist on a dice have odd numbers.

jeka57 [31]3 years ago

3 0

Answer:

1/2 probability of getting an odd number

Step-by-step explanation:

Dice have the given outcomes of getting a 1, 2, 3, 4, 5, or 6. Considering that the desired outcomes are only 3 out of 6 of those given outcomes, that leaves us with a 3/6 or 1/2 chance of getting an odd number.

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Which ordered pair is not a solution of f(x) = 2x + 9? (0, 9) (7, 23) (3, 14) (2, 13)

12345 [234]

(3,14) because when you plug in the x and y values you don’t end up with a true statement.
F(x)=2(3)+9
F(x)=6+9
F(x)=15
14 does not equal 15

4 0

3 years ago

Read 2 more answers

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

Are the following expressions equivalent 5(2z+3) and (5x2)+(z+3)

alexdok [17]

Answer: yes they are

Step-by-step explanation:

3 0

2 years ago

What is the area of the given rectangle?

Salsk061 [2.6K]

Answer:

15 square inches

Step-by-step explanation:

area of retangle =L×B

area of rectangle =5×3=15

3 0

2 years ago

I BET NO ONE KNOWS THIS y varies jointly as x and z. y=20 when x=2 and z=5 . Find y when x=3 and z=6

Greeley [361]

Hello!

If y varies jointly with x and z, it'll mean that x and z are being multiplied by a factor "k", to equal y.

To give you a visual, this is what I mean.

$y=kxz$

That means we'll want to find $k$ with the first point we're given: $(2,20,5)$

$20=k(2)(5)$

$20=10k$

$k=2$

Which means our equation is:

$y=2xz$

Now, let's plug in the $x$ and $z$ from the other point to find $y$ .

$y=2(3)(6)$

$y=36$

Hope this helps!

6 0

2 years ago