Her bank account will be at $9,440 and the end of the second year
6t^-7 * 3t^5 = 1/6t^7 * 3t^5
9514 1404 393
Answer:
$55,811.91
Step-by-step explanation:
The amount with interest is given by the formula ...
A = P(1 +r)^t
where r is the annual interest rate and t is the number of years.
A = $25000(1.055^15) ≈ $55,811.91
The amount due at the end of 15 years will be $55,811.91.
![\mathbb P(X\le163)=\mathbb P\left(\dfrac{X-155}7\le\dfrac{163-155}7\right)\approx\mathbb P(Z\le1.1429)\approx0.8735](https://tex.z-dn.net/?f=%5Cmathbb%20P%28X%5Cle163%29%3D%5Cmathbb%20P%5Cleft%28%5Cdfrac%7BX-155%7D7%5Cle%5Cdfrac%7B163-155%7D7%5Cright%29%5Capprox%5Cmathbb%20P%28Z%5Cle1.1429%29%5Capprox0.8735)
which puts the student at about the 87th percentile.
1.6 i think
add all the goals and divide by the amount of games?