All categories

3 years ago

URGENT PLEASE ANSWER inverse function see attachment

Mathematics

1 answer:

Mila [183]3 years ago

4 0

Answer:

Horizontal shift to the RIGHT of <u>one unit</u>

Step-by-step explanation:

When looking at a square root equation, the transformation form is:

$f(x) = a\sqrt{b(x-h)} +k$

'h' represents a horizontal shift of the graph. Therefore, in this instance:

$f(x) = \sqrt{x-1}$

This means that there is a horizontal shift to the RIGHT of <u>one unit.</u>

You might be interested in

Which inequality is represented in the number line below?-5-4-3-2-1 0 1 2 3 4 5OA.-7+2<22+3<4+2OB.-9≤-3x-6≤6OC.-6 ≤ x + 2

S_A_V [24]

The Solution:

The correct answer is [option B]

Given:

Required:

To determine the inequality represented by the given number line.

7 0

1 year ago

Find the solution to the system of equations x + y = 9 and x - y = -1.

Galina-37 [17]

Answer:

(4, 5 )

Step-by-step explanation:

x + y = 9 → (1)

x - y = - 1 → (2)

adding the 2 equations term by term will eliminate y

2x + 0 = 8

2x = 8 ( divide both sides by 2 )

x = 4

substitute x = 4 into either of the 2 equations and solve for y

substituting into (1)

4 + y = 9 ( subtract 4 from both sides )

y = 5

solution is (4, 5 )

6 0

2 years ago

Read 2 more answers

a. For what values of x does f (x )equals 3 x plus 3 sine x have a horizontal tangent line? b. For what values of x does f (x )

laila [671]

Answer:

(a)Therefore the value of x= $\pi$

(b) Therefore the value of x $=\frac{\pi}{2}$

Step-by-step explanation:

Horizontal tangent line: The first order derivative of a function gives the slope of the tangent of the function. The slope of horizontal line is zero.If the slope of tangent line is zero then the tangent line is called horizontal tangent line.

(a)

Given function is,

$f(x)= 3x+3sin x$

Differential with respect to x

$f'(x)=3+3cos x$

For horizontal tangent line, f'(x)=0

3+ 3 cos x= 0

⇒3 cos x=-3

⇒cos x=-1

⇒x = 180° $=\pi$

Therefore the value of x= $\pi$

(b)

Given that, the slope is 3.

Then,f'(x)=3

3+ 3 cos x= 3

⇒3 cos x= 3-3

⇒cos x=0

⇒x = 90° $=\frac{\pi}{2}$

Therefore the value of x $=\frac{\pi}{2}$

5 0

3 years ago

The width of Maya’s poster is 2 inches shorter than the length. The graph models the possible area (y) of Maya’s poster determin

ArbitrLikvidat [17]

200 would be the correct answer

3 0

3 years ago

Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t

Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

$\frac{dy}{dx}=0$ (The slope is zero)

--To obtain vertical tangent lines, the condition is:

$\frac{dy}{dx}=\frac{1}{0}$ (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

$\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}$ = $2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0$