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4 years ago

Which graph represents y as a function of x?

Mathematics

1 answer:

Marrrta [24]4 years ago

5 0

Answer:

B would be your answer

if you don't have more than one point on the x-axis,it will pass the vertical line test

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A valet makes $56 each day that she works and makes approximately $6 in tips for each car that she parks. If she wants to make a

kirill [66]

She needs to park 16 cars.

$152- 56 = 96

96/6= 16

8 0

3 years ago

Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?

romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions $\frac{40}{8}=\frac{x}{10}$ and $\frac{x}{40}=\frac{10}{8}$ . We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

$40*10=8*x$

$400=8x$

$8*x=40*10$

$8x=400$

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

4 0

3 years ago

Read 2 more answers

What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$