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Nana76 [90]
3 years ago
13

Question 1 help! Please!

Mathematics
1 answer:
Brut [27]3 years ago
6 0

Answer: D

Step-by-step explanation:

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B 7

Step-by-step explanation:

Since the triangles are similar by AAA

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5                 15

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Using cross products

5 * 21 = 15 *x

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we are given

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8 0
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Which expression is equivalent to sec^2xcot^2x?
Lady_Fox [76]
\sec x=\dfrac{1}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}


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