Answer:
dA/dt = k1(M-A) - k2(A)
Step-by-step explanation:
If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)
Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:
Rate Memorized = k1(M-A)
Where k1 is the constant of proportionality for the rate at which material is memorized.
At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:
Rate forgotten = k2(A)
Where k2 is the constant of proportionality for the rate at which material is forgotten.
Finally, the differential equation for the amount A(t) is equal to:
dA/dt = Rate Memorized - Rate Forgotten
dA/dt = k1(M-A) - k2(A)
Answer:
Step-by-step explanation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:Substitute what y equals in the second equation for y in the first equation:
Answer:
Step-by-step explanation:
From the given diagram,
i. ACBD - circle
ii. AB = secant
ii. CD = diameter
iii. EC, EB, ED, GF and GH - radii
iv. D, C, H and F - points of tangency
v. ACB - segment
vi. CBD - semicircle
vii. CBE, BDE and FHG - sectors
vii. E and G - centers of the given circles
viii. BH and DF - tangents
ix. DAB and HF - major segments
x. EDF, EBH, GHB - right angles
xi. DA, AC, CB, BD and FH - minor arcs