The lcm of 54 and 81 is the smallest positive integer that divides the numbers 54 and 81 without a remainder. Spelled out, it is the least common multiple of 54 and 81
Step-by-step explanation:
Consider the LHS, after the 5th step, consider the RHS





Consider the RHS





A(1)=2*5^1-1=2*5^0=2*1=2
a(4)=2*5^4-1=2*5^3=2*125=250
a(8)=2*5^8-1=2*5^7=2*78,125=156,250
Answer:
4 and 5
Step-by-step explanation:
4 and 5 are the co efficients of c
The problem ask to calculate the size of the sample space of this two-stage experiment. Base on the data given and with my calculation. I came up with an answer of that the sample space is 2 times 26 and the size if 52. I hope this helps