Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
g = -18.3
Step-by-step explanation:
3g-10=-45
+10 (Cancel out the 10)
3g=-55
/3 (Divide by 3 to cancel out the 3)
g= -18.3
Answer:
Step-by-step explanation:
The quadratic can be solved in a straightforward way:
This tells you that the solutions are ...
2i or -2i
__
For each root of "a", (x -a) is a factor. Thus the factors of the equation are ...
(x +2i)(x -2i)
Answer:
1) 160 2) 218.64
Step-by-step explanation:
v=lwh (length)×(width)×(height)÷3
1. 10× 6× 8= 480÷3
2. 10.6× 9.1× 6.8= 655.928 ÷ 3 =218.6426 (218.64)
2.) 6k - 9
*can't see #3*
4.) -9p + 17
5.) -15b^2 - 1b + 6c
6.) -4j
