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3 years ago

What is -9 to the-3/2 power with no decimals

Mathematics

1 answer:

nikdorinn [45]3 years ago

6 0

Your answer is -1/27

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Simplify: (2x-3)(4x+1)

mixas84 [53]

Answer:

$8x^2-10x-3$

Step-by-step explanation:

$(2x-3)(4x+1)$

$2x(4x+1)-3(4x+1)$

$8x^2+2x-12x-3$

$8x^2-10x-3$

3 0

3 years ago

Data were collected on the number of days per week that members visit a certain fitness center. The values varied from 0 to 7, a

pshichka [43]

Answer:

Step-by-step explanation:

choice A is not guaranteed since the values varied from 0 to 7.

choice B seems alright, but doesn't include about or anything about the long run.

choice C is incorrect because 50% are less than 3.12 and 50% are greater than 3.12.

choice D seems pretty good, since it says average, long run, approach, etc.

choice E is incorrect because it says "will be". It is not definite.

8 0

3 years ago

Which table shows a proportional relationship between x and y?

Semenov [28]

Answer:

Step-by-step explanation:

A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.

Table A

$\frac{12}{3} \neq \frac{15}{6} \neq \frac{18}{8} \neq \frac{20}{10}$

These fractions are not equal. This is not proportional.

Table B

$\frac{0.5}{1}=\frac{1}{2} =\frac{3.5}{7} =\frac{4}{8}$

These fractions are equal and each shows the numerator to be half of the denominator. This is proportional.

Table C

$\frac{1}{3}\neq \frac{2.5}{7.5} \neq \frac{4}{15} \neq \frac{6}{20}$

These fractions are not equal. This is not proportional.

Table D

$\frac{7}{2} \neq \frac{9}{3}\neq \frac{11}{4} \neq \frac{13}{5}$

These fractions are not equal. This is not proportional.

3 0

3 years ago

6x+9y-12=0 ‎‎‎‎‎ ‎‎‎‎

77julia77 [94]

Answer:

x = 2

Step-by-step explanation:

$6x + 9y - 12 = 0 \\ 6x + 9 \times 0 - 12 = 0 \\ 6x + 0 - 12 = 0 \\ 6x - 12 = 0 \\ 6x = 12 \\ x = 2$

6 0

2 years ago

Solve for c of the right triangle

Ede4ka [16]

In order to solve this triangle we must use cosine law:
$c^{2} = a^{2} + b^{2} - 2ab*cosC$

Now let's plug in the values we are given:
$c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67$
$c^{2} = 25 + 64 - 80*cos67$
$c = \sqrt{80-cos67}$

5 0

3 years ago

Read 2 more answers