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3 years ago

On the first day of the play the auditorium was one third full if this. Pattern continues full will it be on the fourth day?

Mathematics

1 answer:

tigry1 [53]3 years ago

7 0

First day=1/3. Second=2/6 third=4/12 fourth=8/24

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Find f(x) and g(x) so the function can be expressed as y = f(g(x)).

DanielleElmas [232]

$\bf \begin{cases}
f(x)=\cfrac{8}{x}+4\\\\
g(x)=x^2
\end{cases}\qquad f(\ g(x)\ )=\cfrac{8}{\underline{g(x)}}+4\implies f(\ g(x)\ )=\cfrac{8}{\underline{x^2}}+4$

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3 years ago

Find the pattern. What numbers come next?

rusak2 [61]

The answer is B. It is increasing by 9 each time.

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2 years ago

find the ninth term of the geometric sequence, given the first term and the common ratio: a1=1, r=-1/3

olasank [31]

Answer:

0.0001524

Please Mark Brainliest If This Helped!

3 0

2 years ago

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago

a bank offers a home improvement loan with simple interest at an annual rate of 12% j.t. borrows $14000 over a period of 3 years

I am Lyosha [343]

Interest = PRT/100
I= 14000*0.12*3
I=5040

Add Interest to the Principal
14000 + 5040
= $19,040
A is the answer.

3 0

3 years ago