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goldfiish [28.3K]
3 years ago
8

Can anyone answer ...please

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
It is 12 because:
18/6=x/4
Multiply 4 on either side
72/6=x
Simplify
12=x

Hope this helps!!

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There are 600 counters in a bag 90 of them are yellow.
klio [65]
3 over 20 is the fraction in simplest form.
8 0
2 years ago
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Help with these questions
balandron [24]

9514 1404 393

Answer:

  16) No

  17)  (c)

Step-by-step explanation:

For a lot of multiple-choice matrix problems, a simple test is all that is needed to determine the correct answer.

16) The determinant of A is (-2)(-2) -(2)(-3) = 10. So, we expect to see values in the inverse matrix that are 0.2 and 0.3. Alas, they're not there. The matrices are not inverses.

  A^-1 = [[-.2, .3][-.2, -.2]]

__

17) The matrices are both 3×3, so their product is possible (eliminates choice D). The upper left term is different among the answer choices, so we can determine the correct one by computing that term only.

  BA=C

  c11 = (5)(1) +(7)(5) +(3)(-1) = 5 +35 -3 = 37

This matches the third choice (C).

If you use a calculator to compute the full matrix product, it matches choice C in all details.

6 0
3 years ago
A movie theater sold 1,246 tickets this weekend. If 314 tickets were sold on Friday and 529 tickets were sold on sunday
Lisa [10]

Answer:

Saturday=403 tickets

Step-by-step explanation:

1246-314-529=403

6 0
2 years ago
There are 6 rotten mangoes and 24 good mangoes in a bag. What fraction of the mangoes is rotten?
dem82 [27]

\sf \bf {\boxed {\mathbb {Given:}}}

Total number of rotten mangoes in the bag = 6

Total number of good mangoes in the bag = 24

\sf \bf {\boxed {\mathbb {To\:find:}}}

Fraction of the rotten mangoes to the total mangoes.

\sf \bf {\boxed {\mathbb {Solution:}}}

\implies {\blue {\boxed {\boxed {\purple {\sf { \frac{1}{5} }}}}}}

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation :}}}

Total number of mangoes in the bag = Total number of rotten mangoes + Total number of good mangoes

➺\:6 + 24

➺\:30

Now,

Fraction = \frac{Total \: \:   number  \:  \: of \:  \:  rotten \:  \:  mangoes}{Total  \:  \: number  \:  \: of \:  \:   mangoes}

➺\:  \frac{6}{30}

➺\:  \frac{1}{5}

Therefore, the fraction of the rotten mangoes to the total mangoes is \sf\pink{\frac{1}{5}}.

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

6 0
3 years ago
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Question is in the pictures.
Kipish [7]
<h3>Answer:</h3>

x/tan(x) is an even function

sec(x)/x is an odd function

<h3>Explanation:</h3>

<em>x/tan(x)</em>

For f(x) = x/tan(x), consider f(-x).

... f(-x) = -x/tan(-x)

Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...

... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)

The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.

_____

<em>sec(x)/x</em>

For g(x) = sec(x)/x, consider g(-x).

... g(-x) = sec(-x)/(-x)

Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...

... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)

The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.

6 0
2 years ago
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