1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
qwelly [4]
3 years ago
5

What does 25000(1-0.8)^8 equal

Mathematics
2 answers:
Akimi4 [234]3 years ago
7 0

Answer:

0.064

Step-by-step explanation:

  25000(1-0.8)^8

= 25000(0.2)^8

= 0.064

Orlov [11]3 years ago
5 0

Answer:

Step-by-step explanation:

0.064

You might be interested in
I have problems in solving this questions<br> f(x)=x2+6x+3<br> t (x)= x-3/x+4<br> then find (f.t)(x)
zlopas [31]
I need a bad bleep umm Addison Rae??
3 0
3 years ago
Which ordered pair named the location of Melinda's house?
kati45 [8]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ME I WILL GIVE BRSAINLIEST
Fittoniya [83]

hope you a great day

</p>
5 0
2 years ago
Read 2 more answers
Please don’t judge me please if I don’t know
vladimir2022 [97]

Answer:

its ok

Step-by-step explanation:

there is this app called photo math where you take a picture of the problem and its answers you but the answer is -4g

8 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Other questions:
  • The equation 22 + 0.15p =c
    8·1 answer
  • Which statement could be used to explain why f(x)=2x-3 has an inverse relation that is a function
    8·2 answers
  • Why do some numbers from perfect squares and others do not? <br> 3,5,6,8
    9·1 answer
  • HELP ASAP Three generous friends, each with some cash, redistribute their money as follows: Ami gives enough money to Jan and To
    9·1 answer
  • A= 1/2 h (a+b) solve for h
    8·1 answer
  • Part B: Which of the following statements
    11·1 answer
  • 15.268 divided by 10,000 I WILL RATE YOU 5 STARS AND LIKE
    13·1 answer
  • 9x-6+11x what would the answer be
    9·1 answer
  • 193 is what percent of 256? Round to the nearest thousandth.
    5·1 answer
  • HELP WITH NUMBER 13 please
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!