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patriot [66]
3 years ago
5

If its total loss $490 for the week,what was its average daily change?

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0
Divide by 7 (the number of days in a week)
70
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Quadrilateral ABCDABCD has vertices AA (-2, 2), BB (4, 5), CC (3, 0) and DD (-3, -3). What are the coordinates of the midpoint o
Arada [10]
Check the picture below.

the quadrilateral is a parallelogram, thus the diagonals bisect each other, so, we could have used either diagonal, and get the same midpoint.


\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 4}}\quad ,&{{ 5}})\quad 
%  (c,d)
D&({{ -3}}\quad ,&{{ -3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3+4}} }{2}\quad ,\quad \cfrac{-3+5}{2} \right)

6 0
4 years ago
There are 32 patients in a waiting room, and 8 of them are children. What is the child to adult ratio (expressed in the lowest t
jeyben [28]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Graph the function <br> f(x) = -(x - 2)^2 +4.
Romashka-Z-Leto [24]
(0,0)
(1,3)
(2,4)
(3,3)
(4,0)
Vertex is (2,4)
6 0
3 years ago
On the first
liubo4ka [24]

Answer:

0.93

Step-by-step explanation:

u have to add them all and divide by 12. then u add all of them but the outlier and divide by 11. then u subtract.

4 0
3 years ago
Hello! How do I find the surface area of this prism? Thanks!
Studentka2010 [4]
Answer: Choice C) 124 square cm

------------------------------------------------------------------

Explanation:

Let's calculate the area of the trapezoid shown
b1 and b2 are the parallel bases; h is the height of the 2D trapezoid
b1 = 2
b2 = 5
h = 1.5

A = h*(b1+b2)/2
A = 1.5*(2+5)/2
A = 1.5*7/2
A = 10.5/2
A = 5.25
The area of one 2D trapezoid is 5.25 sq cm
There are two of these trapezoids that form the base faces of the trapezoidal prism. So the total base area is 2*5.25 = 10.5 sq cm
Keep this value (10.5) in mind. We'll use it later.

------------

Now onto the lateral surface area (LSA)
It turns out that the formula for the LSA is
LSA = p*d
where 
p = perimeter of the trapezoid shown
d = depth or height of the 3D trapezoid (I'm not using h as it was used earlier)
This formula works for any polygonal base. It doesn't have to be a trapezoid.

In this case the perimeter is,
p = 1.7+2+2.65+5
p = 11.35

So
LSA = p*d
LSA = 11.35*10
LSA = 113.5

Add this LSA to the base area found earlier
10.5+113.5 = 124

The total surface area is 124 square cm
8 0
4 years ago
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