If its total loss $490 for the week,what was its average daily change?

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

pav-90 [236]

Answer:

The solution to f(x) = s(x) is x = 2012.

Explanation:

Rewrite the table and the choices for better understanding:

Enrollment at a Technical School

Year (x) First Year f(x) Second Year s(x)

2009 785 756

2010 740 785

2011 690 710

2012 732 732

2013 781 755

Which of the following statements is true based on the data in the table?

The solution to f(x) = s(x) is x = 2012.

The solution to f(x) = s(x) is x = 732.

The solution to f(x) = s(x) is x = 2011.

The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012, x = 2012.

Thus, the correct choice is the third one:

The solution to f(x) = s(x) is x = 2012.

8 0

3 years ago

Express 0.24 as a percent

Hatshy [7]

Answer: 24%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050

Alborosie

5

Answer:

1050

Step-by-step explanation:

Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.

There is a easier method.

E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference

Back to the problem, we can use the sum of arithmetic series formula,

$y = x( \frac{z {}^{1} + {z}^{n} }{2} )$

Where x is the number of terms in our sequence. Z1 is the fist term of our series. ZN is our last term. And y is the sum of all of the terms

The first term is 5, the numbers of terms being added is 20 because 100/5=20. The last term is 100.

$y = 20( \frac{5 + 100}{2} )$

$y = 20( \frac{105}{2} )$

$y = 1050$

5 0

3 years ago

There is a clown's face on the top of a spinner. The tip of his hat rotates to (−2, 5) during one spin. What is the cosine value

uranmaximum [27]

Remark
The point value is (-2,5) So we know the two sides. We need the hypotenuse. We should notice that the x value is minus (-2) and value is y value is plus (5). That means we are in quad 2. Be careful how you read that. (-2,5) is a point. It is not a tangent.

Step One
Find the hypotenuse.

a = - 2
b = 5
c = ??

c^2 = a^2 + b^2
c^2 = (-2)^2 + 5^2
c^2 = 4 + 25
c^2 = 29 Take the square root of both sides.
sqrt(c^2) = sqrt(29)
c = sqrt(29)

Step Two
Find the Cosine of the angle.
Cosine(theta) = adjacent / hypotenuse
Cosine(theta) = -2 / sqrt(29) <<<<<<< Answer

Again, watch out for what you are given.

6 0

3 years ago

An analyst at Umbrella Corporation studied the relationship between the sales (in millions of dollars) of a product (Y) and popu

Sunny_sXe [5.5K]

Answer:

OPTION A: The company can be 95% confident, based on the method used to calculate the interval, that the true increase in mean sales for each additional 1 million persons in the marketing district is between $453,000 and $1,060,000.

Step-by-step explanation:

Note that the slope here is the increase in sales (in millions of dollars) per every 1 million increase in population. Hence, as this is a confidence interval for the slope, then

OPTION A: The company can be 95% confident, based on the method used to calculate the interval, that the true increase in mean sales for each additional 1 million persons in the marketing district is between $453,000 and $1,060,000.

5 0

4 years ago