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user100 [1]
3 years ago
9

The dogs in an animal parade are grouped by size. There are 18 small dogs, 12 medium-sized dogs, and 10 large dogs. If one dog i

s randomly chosen to lead the parade, what is the probability that a medium-sized dog will be chosen
Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

0.3

Step-by-step explanation:

Given:

Number of small dogs = 18

Number of medium-sized dogs = 12

Number of large dogs = 10

To find: probability that a medium-sized dog will be chosen

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Total number of dogs = 18 + 12 + 10 = 40

Number of medium-sized dogs = 12

So,

probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs = \frac{12}{40}=0.3

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The first few prime numbers:  {2, 3, 5, 7, 11, 13, 17, 19}

One way to start is to divide by the first prime until you can't do that any more, then try the next prime and so on until all the numbers in your list are prime.

40 = 2(20)  divide 20 by 2 again

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Answer:

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