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user100 [1]
3 years ago
9

The dogs in an animal parade are grouped by size. There are 18 small dogs, 12 medium-sized dogs, and 10 large dogs. If one dog i

s randomly chosen to lead the parade, what is the probability that a medium-sized dog will be chosen
Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

0.3

Step-by-step explanation:

Given:

Number of small dogs = 18

Number of medium-sized dogs = 12

Number of large dogs = 10

To find: probability that a medium-sized dog will be chosen

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Total number of dogs = 18 + 12 + 10 = 40

Number of medium-sized dogs = 12

So,

probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs = \frac{12}{40}=0.3

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MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB = \sqrt{(0-6)^2+(6-5)^2} = \sqrt{37}

BC = \sqrt{(6-5)^2+(5+1)^2} = \sqrt{37}

AC = \sqrt{(0-5)^2+(6+1)^2} = \sqrt{74}

Perimeter = \sqrt{37}+\sqrt{37}+\sqrt{74}

                = 6.08 + 6.08 + 8.60

                = 20.76

                ≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

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3 years ago
a mother is five times old as her daughter. in 6 years, the mother will be three times as old as her daughter. how old is each n
Westkost [7]

Answer:

30,6

Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

You can tell because they're selling more and more every month.

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Answer:

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Step-by-step explanation:

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