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denis23 [38]
4 years ago
14

Quadrilateral ABCDABCD has vertices AA (-2, 2), BB (4, 5), CC (3, 0) and DD (-3, -3). What are the coordinates of the midpoint o

f diagonal

Mathematics
1 answer:
Arada [10]4 years ago
6 0
Check the picture below.

the quadrilateral is a parallelogram, thus the diagonals bisect each other, so, we could have used either diagonal, and get the same midpoint.


\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 4}}\quad ,&{{ 5}})\quad 
%  (c,d)
D&({{ -3}}\quad ,&{{ -3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3+4}} }{2}\quad ,\quad \cfrac{-3+5}{2} \right)

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Answer:

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Step-by-step explanation:

Given:

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To Find:

AB = side of the octagon = ?

Solution:

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We Know that,

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substituting the given values in equation we get

54 = Perimter\times \frac{4}{2}\\ \\\therefore Perimeter=\frac{54}{2}\\ \\\therefore Perimeter = 27\ cm\\

Now,

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∴               27  = 8 × AB

∴    AB =\frac{27}{8}\\ \\\therefore AB =3.375\ cm\\\\

After rounded to nearest 10th we get

AB =3.4 cm

The length of line segment AB = 3.4 cm.

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