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vichka [17]
3 years ago
14

A self-serve frozen yogurt restaurant charges its customers according to the weight of their filled frozen yogurt cup. So, the a

mount they charge is directly proportional to the weight of the purchase. If they charge $5.04 for a 12-ounce cup, how much do they charge for a cup weighing 8 ounces?
Mathematics
1 answer:
jeyben [28]3 years ago
4 0
If the price of the yogurt is directly proportional to the weight of the purchase, then it can be expressed as:

Price of yogurt = weight of purchase

With the given above, it can be further expressed as:
$5.04 = 12 oz

These can be expressed in ratio form, which is:

5.04/12

Thus, if the cup weighs 8 oz and we don't know how much it costs, then the ratio should be:

n = 8 oz, or in fractions:
n/8

After this, simply equate the two and cross multiply. 
5.04 / 12 = n/8
5.04(8) = 12n
40.32 = 12n

Then solve for n:
40.32 /12 = 12n/12
n = 3.36. 

Thus, the 8 oz. cup of yogurt costs $3.36. 



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2 Dimensional shape with 5 obtuse angle is <em>Pentagon.</em>
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A group of 50 New York psychology students got a mean score of 530 on the psychology GRE with a standard deviation of 80. These
lesantik [10]

Answer: No, New York students are not truly more nerdy than the California students.

Step-by-step explanation:

Since we have given that

Number of students in a group = 50

Mean score of New York psychology = 530

Mean score of California psychology = 515

Standard deviation = 80

So, we will find t-distribution first.

t=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\t=\dfrac{530-515}{\dfrac{80}{\sqrt{50}}}\\\\t=1.32

Let α = 5% = 0.05

So, t_{\alpha,2}=2.920

Since t < t(critical value)

No, New York students are not truly more nerdy than the California students.

3 0
4 years ago
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

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Answer:

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