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3 years ago

Solve the system of equations below.

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

5 0

C - no solution
you take the second solution and times the entire equation by -1
then simply
and you get 0x + 0y = 20

expeople1 [14]3 years ago

5 0

The correct answer is C ^^

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4. What is the system of equations that describes the following graph?

GarryVolchara [31]

Answer:

The system of inequalities is

$y$

$y>0.25x$

Step-by-step explanation:

step 1

Find the equation of the dashed line with negative slope

The line passes through the points

(0,-2) and (-2,0)

Find the slope

$m=(0+2)/(-2-0)=-1$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-1\\b=-2$

substitute

$y=-x-2$

The solution of the inequality is the shaded area below the dashed line

therefore

The equation of the inequality A is

$y$

step 2

Find the equation of the dashed line with positive slope

The line passes through the points

(0,0) and (4,1)

Find the slope

$m=(1-0)/(4-0)=0.25$

Find the equation of the line (direct variation)

$y=kx$

we have

$k=0.25$

substitute

$y=0.25x$

The solution of the inequality is the shaded area above the dashed line

therefore

The equation of the inequality B is

$y>0.25x$

therefore

The system of inequalities is

$y$

$y>0.25x$

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2 years ago

Which ordered pair could be removed from the graph to create a set of ordered pairs that represents a function

geniusboy [140]

Answer:

(1,3) is the answer if this is question because you haven't given graph.

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3 years ago

Simplify 3 to the power of 1

lina2011 [118]

3 to the power of 1 simplified, is just 3.

7 0

3 years ago

Read 2 more answers

An english reading list has 9 american novels and 7 english novels. A student must read 5 from the list and at least 3 must be e

Elenna [48]

$_7C_3\cdot {_{13}C_2}=\dfrac{7!}{3!4!}\cdot\dfrac{13!}{2!11!}=\dfrac{5\cdot6\cdot7}{2\cdot3}\cdot\dfrac{12\cdot13}{2}=2730$

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2 years ago

What times what equals 54

KonstantinChe [14]

1x54=54
2x27=54
3x18=54
6x9=54

8 0

3 years ago