take I don't know it's right or wrong I just guessing and saying to u .
78
It’s B! You multiply the height by width
Answer:
![(x^2-4y)(x^4+4x^2y+16y^2)](https://tex.z-dn.net/?f=%28x%5E2-4y%29%28x%5E4%2B4x%5E2y%2B16y%5E2%29)
Step-by-step explanation:
<u>Factoring</u>
We need to recall the following polynomial identity:
![(a^3-b^3)(a-b)(a^2+ab+b^2)](https://tex.z-dn.net/?f=%28a%5E3-b%5E3%29%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29)
The given expression is:
![x^6- 64y^3](https://tex.z-dn.net/?f=x%5E6-%2064y%5E3)
To factor the above expression, we need to find a and b, knowing a^3 and b^3. a is the cubic root of a^3, and b is the cubic root of b^3:
![a=\sqrt[3]{x^6}=x^2](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7Bx%5E6%7D%3Dx%5E2)
![b=\sqrt[3]{64y^3}=4y](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B64y%5E3%7D%3D4y)
Now we apply the identity:
![x^6– 64y^3=(x^2-4y)[(x^2)^2+(x^2)*(4y)+(4y)^2]](https://tex.z-dn.net/?f=x%5E6%E2%80%93%2064y%5E3%3D%28x%5E2-4y%29%5B%28x%5E2%29%5E2%2B%28x%5E2%29%2A%284y%29%2B%284y%29%5E2%5D)
Operating:
![x^6– 64y^3=(x^2-4y)[x^4+4x^2y+16y^2]](https://tex.z-dn.net/?f=x%5E6%E2%80%93%2064y%5E3%3D%28x%5E2-4y%29%5Bx%5E4%2B4x%5E2y%2B16y%5E2%5D)
The remaining factors cannot be factored in anymore. Thus the completely factored form is:
![\boxed{(x^2-4y)(x^4+4x^2y+16y^2)}](https://tex.z-dn.net/?f=%5Cboxed%7B%28x%5E2-4y%29%28x%5E4%2B4x%5E2y%2B16y%5E2%29%7D)
Step-by-step explanation:
Given
f(x) = 6x - 5
f^-1(x) = ?
Let
y = f(x)
y = 6x - 5
Interchanging the roles of x and y we get
x = 6y - 5
6y = x + 5
y = ( x + 5 ) / 6
So therefore f^- 1(x) = (x + 5) / 6
Hope it helps :)❤