Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
i.e.
i.e.
i.e.
i.e.
i.e.
i.e.
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is .
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.
Answer:
The zeros are 0, 4, 6.
The y-intercept is 0.
Step-by-step explanation:
f(x) = x^3 - 10x^2 + 24x
x^3 - 10x^2 + 24x = 0
x(x^2 - 10x + 24) = 0
x(x - 4)(x - 6) = 0
x = 0 or x - 4 = 0 or x - 6 = 0
x = 0 or x = 4 or x = 6
y-intercept:
Since x = 0 is a root, that means that the point (0, 0) is part of the function. That makes the y-intercept 0.
You can also solve for the y-intercept by letting x = 0 in the function and solving for f(0).
Let x = 0.
f(0) = 0^3 - 10(0^2) + 24(0)
f(0) = 0
y-intercept: 0
Answer:
n
Step-by-step explanation:
Plug in each possible value into the equation.
when m = 5
2k = m + 3
2k = (5) + 3
Simplify
2k = 8
isolate the k, divide 2 from both sides
2k/2 = 8/2
k = 8/2
k = 4
When m = 5, k = 4
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2k = m + 3
when m = 7
2k = (7) + 3
2k = 10
2k/2 = 10/2
k = 10/2
k = 5
when m = 7, k = 5
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2k = m + 3
When m = 9
2k = (9) + 3
2k = 12
2k/2 = 12/2
k = 12/2
k = 6
when m = 9, k = 6
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hope this helps
So since there are 2 placeholders, the answer are many, but we can make into slope intercept form to make it easier to solve (slope intercept form is y=mx+b)
15x-12y=60
15x-60-15y=0
15x-60=12y
12y=15x-60
divide both sides by 3
4y=5x-20
divide both sides by 4
y=5/4x-5
just put in values for x and get y so exg
(x,y)
0,-5
1,-15/4
2,-5/2
3,-5/4
4,0
and so on