$\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}$

Or, if you mean (r+3Q)/h=t:

$\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}$

4 0

2 years ago

Combine terms: 12a + 26b -4b – 16a.

Kryger [21]

Answer:

c. -4a + 22b

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

(4x-1) = 6<br> 2<br> How to solve rational equations

9966 [12]

Answer:

educated guess

Step-by-step explanation:

cos ( 390 ) sin ( 330 ) − 4 cot ( − 45 )

8 0

2 years ago

Identify the domain of the graph given. *Don't forget the parenthesis or brackets*

anzhelika [568]

Answer:

(-4,3)

Step-by-step explanation:

The domain of a function is all of its possible x-values. In this graph, there is a y-value for every x-value between -4 and 3 except -4 and 3, because there are open dots at those points. Therefore, the domain is (-4,3). Use parenthesis because the function is not defined at x=-4 or x=3.

5 0

3 years ago