The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
So
lets say we have
a/b=2a/2b
we know that if we invert one and multiply it by the other (divide them), we get 1 because a/a=1 where a=a
so
2/3 and 4/6 are equivelent because if you divide them we get 12/12=1
2/3 and 8/12 are equivilent because if you divide them we get 24/24=1
and sinde 2/3=4/6 and 2/3=8/12, 2/3=4/6=8/12
they are equivlent
-3 is an integer and a rational number.
Natural numbers and while numbers refer to positive numbers, so -3 cannot be either of those.
Answer:
N = 9
M = 87.11
Step-by-step explanation:
According to the situation, the data provided and the solution are as follows
The scores for the student in the classroom is
= 88 88 92 88 88 72 96 88 84
The different student's number of scores is 9
The solution of new n and M is shown below:-
Sample size (n) = 9
Sample mean (m) is

= 

= 87.11