Octagon = 8-side polygon
<u>Find area of 1 triangle:</u>
Area of one side triangle = 60 ÷ 8 = 7.5 m²
<u>Given area and length, find height:</u>
Area of each triangle = 7.6 m²
Length of each triangle = 3m
Area = 1/2 x base x height
7.5 = 1/2 x 3 x height
Heigth = 5m
Answer: Slanted Height = 5 m
<h3>
Answer: 80 meters</h3>
This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).
So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.
a^2 + b^2 = c^2
x^2 + (60)^2 = (100)^2
x^2 + 3600 = 10000
x^2 = 10000 - 3600
x^2 = 6400
x = sqrt(6400)
x = 80
Each smaller right triangle has side lengths of 60, 80, 100
Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.
The answer to your equation is x=2.52
Answer:
X=7 ST=11 RT=17
Step-by-step explanation:
RT=RS+ST. RS= 2(7)-8. ST=11
X+10=2x-8+11. =14-8=6. RT= x+10
X+10=2x+3. RS=6. 7+10=17
10=x+3. RT=17
X=7
The answer is 21 - 17, which = 4.
Or you could +4 to CM (17) which equals CQ (21)