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3 years ago

What is the difference between -4 and 6

2 answers:

5 0

 $answer = - 10 \\ solution \\ - 4 - 6 \\ = - 10 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$ 

Ipatiy [6.2K]3 years ago

3 0

Answer:

$- 10$

Step-by-step explanation:

We know that,

$( - ) \times ( + ) = ( - )$

$( - ) + ( - ) = ( - )$

Let's solve

$- 4 - ( + 6) \\ - 4 - 6 \\ = - 10$

hope this helps

brainliest appreciated

good luck! have a nice day!

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The length of a rectangle is 1 ft less than double the width, and the area of the rectangle is 21 ft^2. Find the dimensions of t

ICE Princess25 [194]

Let the width be w, then length = 2w - 1

Area = length times width = w(2w - 1) = 21.

Thus, 2w^2 - w = 21 or 2w^2 - w - 21 = 0

Solving the quadratic equation gives that w = 3.5.

Therefore, width is 3.5 ft and length is 2(3.5) - 1 = 6 ft.

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3 years ago

Ribbon candy cost 2.50 per foot. How many feet can you buy if you have 11.25?

netineya [11]

Answer: your answer is 4.5

Step-by-step explanation: your answer is 4.5 because 11.25/2.50=4.5

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2 years ago

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If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

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3 years ago

What is the triangle's base, b?

Oksi-84 [34.3K]

Answer:

6.928 or 6.93

Step-by-step explanation:

\sqrt{8^{2}-4^{2}}

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2 years ago

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Can someone help me with this?

Alla [95]

Answer:

d and e

Step-by-step explanation:

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3 years ago