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Crazy boy [7]
3 years ago
11

What is the approximate area of the circle that fits perfectly inside of the square? Use Pi = 3.14 and round to the nearest tent

h.The base is 5 cm

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

19.625\text{ cm}^2

Step-by-step explanation:

GIVEN: A square with base 5\text{ cm}, a circle that perfectly fits inside square.

TO FIND: Approximate area of circle.

SOLUTION:

Consider the figure attached.

let the radius of circle be x\text{ cm}

radius of circle =\frac{\text{length of base of square}}{2}

                     x=\frac{5}{2}\text{ cm}

                     x=2.5\text{ cm}

Area of circle =\pi(radius)^2

                      =3.14\times(2.5)^2

                      =19.625\text{ cm}^2

Hence the area of circle that perfectly fits inside the square is 19.625\text{ cm}^2

SVEN [57.7K]3 years ago
3 0

Answer:

19.6

Step-by-step explanation:

just took it bro

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The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.
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Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=5 , we get,

V=\frac{4}{3} (3.14)(125)

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Rounding off to two decimal places, we have,

V=523.33 \ in^3

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Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = \frac{3}{4} (5)=3.75

Radius of the third sphere = \frac{3.75}{2} =1.875

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=1.875 , we get,

V=\frac{4}{3} (3.14)(1.875)^3

V=\frac{4}{3} (3.14)(6.59)

V=27.5901 \ in^3

Rounding off to two decimal places, we have,

V=27.59 \ in^3

Thus, the volume of the third sphere is 27.59 in³

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