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lord [1]
4 years ago
7

Please help me asa[pasasppapspaspaspasppss

Mathematics
1 answer:
tigry1 [53]4 years ago
3 0

Answer:

B

Step-by-step explanation:

The smaller one is divided by 2 and is reflected around the y-axis

(i'm not good at explaining)

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The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability d
ale4655 [162]

Answer:

Average Mean = 1.8

Step-by-step explanation:

Missing:

X:0 1 2 3 4 5 6

P(x): 0.20 0.30 0.20 0.15 0.10 0.05

Computation:

Average Mean [Probability distribution]

∑[P(x) × X]

= 0 x 0.20 + 1 x 0.30 + 2 x 0.20 + 3 x 0.15 + 4 x 0.10 + 5 x 0.05

= 1.8

Average Mean = 1.8

5 0
3 years ago
The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
4 years ago
How do you find tax paid
Kobotan [32]

Answer:

You can pay your personal and business taxes to the Canada Revenue Agency (CRA) through your financial institution's online banking app or website. Most financial institutions also let you set up a payment to be made on a future date.

Step-by-step explanation:

step by step

6 0
3 years ago
Read 2 more answers
What grades are considered good?
Dahasolnce [82]

Answer:

Depends who you are and what your standard grades are...

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
4(x+1.5)=38 solve for x
Kitty [74]

Answer:

x = 8

Step-by-step explanation:

4(x+1.5)=38

Distribute the 4

4x +6 = 38

Subtract 6 from each side

4x+6-6 = 38-6

4x = 32

Divide each side by 4

4x/4 = 32/4

x = 8

3 0
4 years ago
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