All categories

3 years ago

The table below represents which equation?

Mathematics

2 answers:

Alex777 [14]3 years ago

8 0

Answer:

The answer is in the solution. Please read to solution because I doubt you know anything about the topic. Read the solution so you can do it yourself next time.

Step-by-step explanation:

For this problem you just have to plug the x and y points into the equation.

Let's try out the easy ones first. If you plug 1 (our x value) into the equation you get y = 3(1) + 2

This then becomes y=5 and the y value that correlates to the x value 1 does NOT equal 5. So we can cross out the third option.

Now let's go to the fourth option (once again I'm just doing the easy ones).

y = -3x + 2

Plug in 1 (the first x value given) and you get y = -3 (1) +2

This then becomes y = -3 + 2.

Solve it and it is -1.

WE ARE NOT DONE THOUGH! Whenever you get a problem like this, plug in all the values.

Let's plug in 2 and -4 now.

y = -3x + 2

y = -3 (2) +2

y = -6 + 2

y = -4

So far so good!

Let's just plug in the other two ordered pairs.

y = -3 (3) + 2

y = -9 + 2

y = -7

Let's just plug in the last ordered pair to make sure.

y = -3x + 2

y = -3 (4) + 2

y = -12 + 2

y = -10

WE ARE DONE!

Leviafan [203]3 years ago

4 0

Eidnwicnssniqbsiwnsoqnziqnswkxso

You might be interested in

How tooo do thissss?

exis [7]

Step-by-step explanation:

m/s² = m/s / s

this is the slope of the line in the graph.

t = 2, that means it is in the first segment of 0 - 6 seconds

the slope in this segment is

(25-15)m/s / (6-0)s

10m/s / 6s = 10/6 m/s² = 5/4 m/s² = 1.25 m/s² ≈ 1.3 m/s²

the same thing for t = 12 in the third segment.

the acceleration or slope is negative here, but that's called here a "forbidden word", and is therefore also a positive number.

in that this segment the slope is

(0-25)m/s / (16-11)s

-25m/s / 5s = -5 m/s²

and so, the answer is 5 m/s².

for the total distance we need to calculate the area under the lines.

the line functions in the 3 segments are :

s(t) = 5/4 t + 15

s(t) = 25

s(t) = -5t + 25

the third one is simplified by moving it from the 11 to 16 seconds interval to a 0 to 5 seconds interval. this creates the same area under that line.

the area under the first line is the integral of the line function between 0 and 6.

that is

[5/8 t² + 15t] between 0 and 6.

and that is

5/8 × 36 + 90 - 5/8 × 0 - 15×0 = 45/4 + 90

= 45/4 + 360/4 = 405/4 = 101.25m

the area under the second segment is simply the area of the rectangle 5×25 = 125m

and the area under the third segment is the integral of the line function between 0 and 5 (remember, we shifted from 11 to 16 to the interval 0 to 5).

that is

[-2.5t² + 25t] in the interval 0 to 5.

and that is

-2.5×25 + 25×5 - -2.5×0 - 25×0 = -62.5 + 125 = 62.5m

as a control check this area is also the area of a right-angled triangle with legs of 5 and 25

the area is 25×5/2 = 125/2 = 62.5

so, it is correct.

the total area under the lines is therefore

101.25 + 125 + 62.5 = 288.75 m ≈ 288.8 m

the average speed is now simply

288.75 m / 16 s = 288.75/16 m/s = 18.046875 m/s ≈

≈ 18 m/s

but if we used the already rounded result of the total distance of 288.8 m, then we would get

288.8 / 16 = 18.05 m/s ≈ 18.1 m/s

3 0

3 years ago

Which number sentence below matches this word problem? Jay had to paint part of the outside of his house. He spent 7 hours paint

sergeinik [125]

Answer:

B! 7+11= 18

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Is A triangle with side lengths 24,32, 42 a right angle?

Effectus [21]

Answer:

No its not a right angle.

3 0

3 years ago

Divide and answer in simplest form: 4/5 ÷ 2

mestny [16]

Answer:

2/5

Step-by-step explanation:

4/5*1/2=4/10=2/5

6 0

4 years ago

Read 2 more answers

In previous tests, baseballs were dropped 24 feet onto a concrete surface, and they bounced an average of 92.82 inches. In a t

goblinko [34]

Answer:

There is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.8292.82 inches, and it appears that the new baseballs are different

Step-by-step explanation:

Given that in previous tests, baseballs were dropped 24 feet onto a concrete surface, and they bounced an average of 92.82 inches

But new balls showed mean of 92.6 inches with s = 1.72 inches

Sample size = 23

Since sample size is less than 30 and population std deviation is not know we use t test

$H_0: \bar x = 92.82\\H_a: \bar x \neq 92.82$

(Two tailed test at 5% significance level)

Mean difference = $92.6-92.82=-1.22$

Std error of sample mean = s/sqrt n = $\frac{1.72}{\sqrt{23} } \\=0.3586$

Test statistic t = mean diff/std error = -3.402

df = 23-1 =22

p value = 0.002559

since p value <5% we reject H0

There is sufficient evidence to support the claim that the new balls have bounce heights with a mean different from 92.8292.82 inches, and it appears that the new baseballs are different

3 0

3 years ago