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In-s [12.5K]
3 years ago
7

Megan bought 2 1/4 pounds of bananas for $0.80 per pound and 1 1/2 pounds of strawberries for $1.10 per pound. How much more did

Megan spend on bananas than on strawberries?
Mathematics
2 answers:
marta [7]3 years ago
4 0

Answer:

$0.15

Step-by-step explanation:

Cost of each pounds of banana = $0.80

Number of pounds of banana = 2 1/4 pounds

Total cost of banana = $0.80 × 2 1/4 pounds

= 0.80 × 9/4

= 0.80 × 2.25

= 1.8

Total cost of banana = $1.8

Cost of each pounds of strawberry = $1.10

Number of pounds of strawberry = 1 1/2 pounds

Total cost of strawberry = $1.10 × 1 1/2 pounds

= 1.10 × 3/2

= 1.10 × 1.5

= 1.65

Total cost of strawberry = $1.65

How much more did Megan spend on bananas than on strawberries?

Total cost of banana - Total cost of strawberry

= $1.8 - $1.65

= $0.15

Dennis_Churaev [7]3 years ago
3 0

Answer:

$0.15

Step-by-step explanation:

Cost of each pounds of banana = $0.80

Number of pounds of banana = 2 1/4 pounds

Total cost of banana = $0.80 × 2 1/4 pounds

= 0.80 × 9/4

= 0.80 × 2.25

= 1.8

Total cost of banana = $1.8

Cost of each pounds of strawberry = $1.10

Number of pounds of strawberry = 1 1/2 pounds

Total cost of strawberry = $1.10 × 1 1/2 pounds

= 1.10 × 3/2

= 1.10 × 1.5

= 1.65

Total cost of strawberry = $1.65

How much more did Megan spend on bananas than on strawberries?

Total cost of banana - Total cost of strawberry

= $1.8 - $1.65

= $0.15

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Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

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  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

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