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geniusboy [140]
2 years ago
9

Evaluate 12C3 Please show your work - Thank you!

Mathematics
2 answers:
NikAS [45]2 years ago
6 0

Answer: 220

Step-by-step explanation:

We know that the combination is a method to determine the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we apply the formula given below:-

^nC_r = \dfrac{n!}{(n-r)!r!}, where n represents the total number of items, and r represents the number of things being chosen at a time.

The given expression : ^{12}C_3

Then by using above formula , we have

^{12}C_3 = \dfrac{12!}{(12-3)!3!}\\\\=\dfrac{12\times11\times10\times9!}{9!\times6}=220

dsp732 years ago
4 0
12C3 means nCr
You have 12 items of which you want to choose 3 and the order in which you choose them does not matter.


n!                 12!                  12!          479001600
----------  =  --------           = -------  =  ----------------- = 220
(r!(n-r)!      3!(12-3)!            3!(9!)         21177280

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a=9

Step-by-step explanation:

a^3 = 729

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Jack's last six scores are 75,78,83,80,79,84. If he scores a 90 on the next test, by how much will his mean test score increase?
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

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= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

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= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
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