Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency = 
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
Answer:
The first is decay, seeing as it is in between 1 and 0
The second is growth, as it is greater than 1
Step-by-step explanation:
It's exponential growth when the base of our exponential is bigger than 1, which means those numbers get bigger. It's exponential decay when the base of our exponential is in between 1 and 0 and those numbers get smaller.
Answer:
10√5 - 5√2
or
5(2√5 - √2)
Step-by-step explanation:
Given:
2√5(5 - 5√5)
Required:
Multiply and simplify
Solution:
2√5(5 - 5√5)
Apply distributive property by multiplying each term in the bracket by 2√5
2√5*5 - 2√5*5√5
2*5√5 - 2*5√5*√5
10√5 - 10√25
10√5 - 10*5
10√5 - 50
10√5 - (25*2)
10√5 - 5√2
Or
5(2√5 - √2)
Answer:
78,000
Explanation:
8,000 is in the thousands place, the 4 in the hundreds place is too low to round it up to 9,000, so it gets rounded down to 78,000.
