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Neporo4naja [7]
2 years ago
14

What is the slope of the line that passes through the points (-2, 3) and (-14, -5) ? ( Write your answer in the simplest form.

Mathematics
1 answer:
Ronch [10]2 years ago
6 0

Answer:

⅔

Step-by-step explanation:

slope = (-5-3)/(-14+2) = -8/-12= ⅔

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skad [1K]

Answer:

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Step-by-step explanation:

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The only solution to this system of equations is the point (0, 4), which lies in the domain.

f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1

\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1

\therefore (0,4) is a saddle point.

Boundary points -  (4,0),  (-4,0), (0,16)

Along boundary  y=16-x^2

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\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}

Therefore, the absolute maximum and minimum is 20\; \text{and} -20.

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3 years ago
(ASAPPP) The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the
prohojiy [21]

Answer:

The instantaneous velocity at t = 2 is -6.

Step-by-step explanation:

We have the position as the function

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The instantaneous velocity at t = 2

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