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Naily [24]
3 years ago
6

In a batch of​ 8,000 clock radios 7​% are defective. A sample of 1313 clock radios is randomly selected without replacement from

the​ 8,000 and tested. The entire batch will be rejected if at least one of those tested is defective. What is the probability that the entire batch will be​ rejected
Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer: Probability that the entire batch will be rejected is 0.611.

Step-by-step explanation:

Since we have given that

Number of clock radios in a batch = 8000

Probability of defective clock radio = 7%

According to question, we have mentioned that A sample of 13 clock radios is randomly selected without replacement from the​ 8,000 and tested.

We will use "Binomial distribution":

here, n = 13 and

p (probability of success) = 7% = 0.07

so, we need to find that

P(the entire batch will be rejected)  = P(at least one of those test is defected)

So, it becomes,

P(at least one of those tested is defective) = 1 - P(none are defective)

So, P(none are defective ) is given by

(1-0.07)^{13}\\\\=0.93^{13}\\\\=0.389

So, P(at least one of those tested is defective) = 1 - P(none are defective)

                                                                             =  1 -  0.389

                                                                             =  0.611

Hence, Probability that the entire batch will be rejected is 0.611.

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Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept form, y = mx + b,
seropon [69]

Answer:

-9

Step-by-step explanation:

What b represents here is the y intercept.

The first thing we will do here is to find the slope.

Mathematically;

m = (y2-y1)/(x2-x1)

Plugging the values;

m = (12-3)/(7-4) = 9/3 = 3

The equation can thus be written as;

y = 3x + b

To get b, we can use any of the points since they lie on the line

Let’s use point M

Substitute the values of x and y in the equation

3 = 3(4) + b

3 = 12 + b

b = 3-12 = -9

3 0
3 years ago
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5 0
3 years ago
What number must be added to 15,-6, and 12 to have a mean of 5? Explain.
Genrish500 [490]

You need to add a -1

We can find this by setting up the equation like so

x + (-6) + 12 + 15 / 4 = 5

x + 21 = 20

x = 20 -21

x = -1

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3 0
2 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
Simplify.<br> 4/x^2-35 - 1/x+5
Oksana_A [137]
If I understand your question well, I suppose you mean \frac{4}{ x^{2} -35} -  \frac{1}{x+5}
\frac{4}{ x^{2} -35} - \frac{1}{x+5} =  \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}
6 0
3 years ago
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