Sin⁻¹(-<img src="https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D" id="TexFormula1" title="-\frac{\sqrt{3} }{2}" a

Svet_ta [14]

#2- yes because both can be divided or multiplied for example 3 and 9, u can multiply 3x3 to get 9 since the dilation is 3 then yes it is similar triangles

4 0

3 years ago

The area of the sahara desert is 7 times the area of the gobi desert if the are of the sahara is approximately 3.5 million squar

Andreyy89

Answer: 500,000

Step-by-step explanation:

3.5M/7=500,000

3 0

2 years ago

If g(x) = x4<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="l

ELEN [110]

Answer: 69,904

Explanation:
g(-16)= (-16)^4-(-16)^3+(-16)^2-(-16)
g(-16)= (65,536)-(-4,096)+(256)-(-16)
g(-16)= 65,536+4,096+256+16
g(-16)=69,904

4 0

3 years ago

The radius of the circle is 3 millimeters. what is the circles area

Irina18 [472]

Answer:

28.26 millimeters

4 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

2 years ago