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Alexus [3.1K]
4 years ago
13

State the rang of relation ? PLSS HELP:(

Mathematics
1 answer:
MAXImum [283]4 years ago
6 0

Answer:

Range is the Y values

{1,-5, 7, 0}

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Thanks you to those who have been helping me with my math homework much appreciation have these points as gratitude!
7nadin3 [17]

Answer:

cool

Step-by-step explanation:

4 0
3 years ago
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Which graph represents the function below?
Andrei [34K]
Plug it into a graphing calculator, I used Desmos. 

The graph is the same as x=-2 and y=-4. All I did was replace g(x) with y since y is the output function and so is g(x), then I just added the whole expression as follows and it graphed it for me. 

The bottom graph to the left is the answer.

I hope this helps!
~kaikers
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3 years ago
What is opportunity cost?
baherus [9]
A venue for lost when choosing between two options (2)
I just did this on edge
8 0
3 years ago
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What is the missing constant term in the perfect square that starts with X^2 - 8x
xenn [34]

Answer:

16

Step-by-step explanation:

Perfect square in the quadratic from ax² + bx + c

You know an equation is perfect when:

2√(ax²)√(c) = bx

Substitute x² for ax² and 8x for bx. Then isolate c by doing the reverse operations.

2√(ax²)√(c) = bx

2√(x²)√(c) = 8x

2x√c = 8x   Divide both sides by 2x

√c = 4    Square both sides to isolate c.

c = 16

The missing constant term is 16.

Check answer:

x² - 8x + 16

(x - 4)²

= (x - 4)(x - 4)

= x² - 4x - 4x + 16

= x² - 8x + 16

3 0
3 years ago
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On planet Zorg, a 30 kg barbell can be lifted by only exerting a force of 180N. What is the acceleration of gravity on Planet Zo
WITCHER [35]
To calculate g, we use the formula F= mg. F is given as 180N, and m is given as 30 kg, therefore:
180N = (30kg)(g)
g = 6 m.s-1.
The motion of this object would be decreased on Earth as more force would be required to lift it. If we assume g is 9.8 m.s-1 on Earth, we can calculate the force required.
F = mg
   = (30kg)(9.8 m.s-1)
   = 294 N

5 0
4 years ago
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