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Kitty [74]
2 years ago
9

Perform the indicated operation. 3m-6/4m+12*m^2+5m+6/m^2-4

Mathematics
1 answer:
Troyanec [42]2 years ago
5 0

Answer:

\frac{3}{4}

Step-by-step explanation:

The given expression is:

\frac{3m-6}{4m+12} \cdot \frac{m^2+5m+6}{m^2-4}

We factor to get:

\frac{3(m-2)}{4(m+3)} \cdot \frac{(m+2)(m+3)}{(m-2)(m+2)}

Cancel out the common factors to get:

\frac{3(m-2)}{4(m+3)} \cdot \frac{(m+3)}{(m-2)}

We cancel further to get:

\frac{3(m-2)}{4(m+3)} \cdot\frac{(m+3)}{(m-2)}=\frac{3}{4}

The correct chice is B.

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Simplify the expression below. ​
Novay_Z [31]

Answer:

\displaystyle 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{7^2 - 13}{24 - 18}<u />

<u />

<u>Step 2: Evaluate</u>

  1. [Fraction] Exponents:                     \displaystyle \frac{49 - 13}{24 - 18}
  2. [Fraction] Subtract:                         \displaystyle \frac{36}{6}
  3. [Fraction] Divide:                             \displaystyle 6
5 0
2 years ago
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
2 years ago
-7(2x+4)+6=7x+20<br> Solve for x
igomit [66]

Answer:

x=1.8

Step-by-step explanation:

4 0
2 years ago
Solve the following: Three times the 1st number plus the 2nd number plus twice the 3rd is 5. If three times the 2nd number is su
Karolina [17]
Three times the 1st number plus the 2nd number plus twice the 3rd is 5 is the same as 3x+y+2z=5. If three times the 2nd number is subtracted from the sum of the 1st and three times the 3rd number, the result is 2 is just x+3z-3y=2. And if the 3rd number is subtracted from two times the 1st number and three times the 2nd, giving a result of 1 means 2x+3y-z=1. Then you use substition on these equations to get a equation where one variable equals 2 others, like using the first to get y=5-2z-3x and then this can be substituted into the other two to get x+3z-3(5-2z-3x)=2 and 2x+3(5-2z-3x)-z=1 we can then simplify and subtract the equations. After simplification we have 10x+9z=17 and 7z+7x=16 which can be turned into 70x+63z=119 and 70x+70z=160 which can be then subtracted to get that 7z=41 and z=41/7. Now we backtrack to a two variable equation like 7z+7x=16 and plug in to find x. So after plugging in we get 41+7x=16 and 7x=-25 so x=-25/7. Now we choose a 3 variable equation and plug in. So taking y=5-2z-3x we plug in 41/7 for z and -25/7 for x to get y=5-82/7+75/7 and y=5-7/7 and y=4. Therefore x = -25/7 y = 4 and z = 41/7.
3 0
3 years ago
How do you work out <br> 5x71
Gwar [14]

Answer:

355

Step-by-step explanation:

8 0
2 years ago
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