Planes Q and R are parallel planes. Plane Q contains line a. Plane R contains line b. If a third plane could be drawn which cont
ains both lines a and b, then lines a and b must be parallel. lines a and b cannot be parallel. lines a and b must be skew. lines a and b must be perpendicular.
2 answers:
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Answer:
x²-10x+25
Step-by-step explanation:
f(x) = x²
<h3>i) substitute the x-5 into x</h3>f(x-5) = (x-5)²
<h3>ii) using the formula (a-b)² = a²-2ab+b², expand the expression</h3>f(x-5) = (x-5)²
= x²-2(5x)+5²
<h3>iii) calculate the products</h3>f(x-5) = x²-2(5x)+5²
= x²-10x+25
* the pic i inserted shows the shape of your graph
