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vaieri [72.5K]
3 years ago
11

Planes Q and R are parallel planes. Plane Q contains line a. Plane R contains line b. If a third plane could be drawn which cont

ains both lines a and b, then lines a and b must be parallel. lines a and b cannot be parallel. lines a and b must be skew. lines a and b must be perpendicular.

Mathematics
2 answers:
MAVERICK [17]3 years ago
3 0
<span>The correct answer is:
lines a and b must be parallel

See the attached figure.

=======================================

Note:
1. skewed lines cannot be in one plane
2. If a and b are </span><span>perpendicular, they shoulde be in plane Q or R

</span>

Paladinen [302]3 years ago
3 0

The answer is:

A) lines a and b must be parallel.


Hope it helps!


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Step-by-step explanation:

2 x 5 = 10

9 x 5 = 45

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NNADVOKAT [17]

Answer:

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*20}{100}= 12

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*25}{100}= 15

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*30}{100}= 18

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces = \frac{60*50}{100}= 30

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

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3 years ago
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Answer:

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Step-by-step explanation:

Hello There!

the measure of supplementary angles add up to equal 180

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4x = x + 6

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x = 2

SQ = 2(2) = 4

TP = 2 + 6 = 8

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4 years ago
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