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Vlad1618 [11]
3 years ago
9

Quadrilateral PQRS has coordinates P(-1,3), Q(7,-1),R(1,-4), and S(-3,-2)

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

man that's hard I'm still in class 6

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Which number(s) below belong to the solution set of the equation? Check all
Stells [14]

Answer:

11

Step-by-step explanation:

198 ÷ 18 = 11

x = 11

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2 years ago
Which products have the same sign as (Negative 2 and StartFraction 3 over 7 EndFraction) (Negative StartFraction 6 over 11 EndFr
avanturin [10]
Answer : A

Hope this helps
5 0
3 years ago
You are considering renting a car from two different rental companies. Proxy car rental company charges. $0.32 per mile plus an
mash [69]
Let y = total charge for a car rental and x = miles driven
Proxy car equation: y = 0.32x + 18
YourPal equation: y = 0.36x + 12

Set equations right sides equal to each other... meaning their cost, y, are equal
0.32x + 18 = 0.36x + 12
18 = 0.04x + 12  (subtract 0.32x from both sides of the equation)
6 = 0.04x            (subtract 12 from both sides of the equation)
150 = x               (divide both sides of the equation by 0.04)
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6 0
3 years ago
What is 2 and 6/7 times 4/5
bulgar [2K]

Answer:

Step-by-step explanation:

2 6/7 * 4/5....turn ur mixed number into an improper fraction and just multiply

20 / 7 * 4 / 5 = 80/35 which reduces to 16/7 or 2 2/7

4 0
3 years ago
Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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