Question

If u(x)=-2x^2+3 and v(x)=1/x what is the range of (u*v)(x) **the picture should help

Answer 1

We have that
$u(x)=-2 x^{2} +3 \\ \\ v(x)= \frac{1}{x}$
$u(v(x))=u( \frac{1}{x})=-2( \frac{1}{x} )^{2} +3 \\ u( \frac{1}{x})= \frac{(3 x^{2} -2)}{ x^{2} }$

using a graph tool
see the attached figure

The horizontal asymptote of this function is at y=3.
So,
the range of this function is from (−∞,3)

Answer 2

Answer:

-OO,3

Step-by-step explanation: