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2 years ago

The table shows the cost of downloading songs from a web site

Mathematics

2 answers:

Vitek1552 [10]2 years ago

6 0

Answer:

I dont see a table :/

Step-by-step explanation:

Anton [14]2 years ago

5 0

The table doesn’t seem to be showing up, please try again so I could help you out :)

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From points A and B, the distance between which is 1020 mi, two trains left simultaneously towards each other. The speed of one

djverab [1.8K]

Complete question :

From points A and B, the distance between which is 1020 mi, two trains left simultaneously towards each other. The speed of one train was 10 mph greater than the speed of the other one. In 5 hours the trains had not met yet and were 170 mi apart. Find the speed of the trains.

Answer:

Train A = 80 miles per hour

Train B = 90 miles per hour

Step-by-step explanation:

Given that :

Distance between A and B = 1020

Let the speed of A = x

Speed of B = x + 10

Since they both left simultaneously;

Distance traveled after 5 hours will be :

Distance = speed * time

A = x * 5 = 5x

B = (x + 10) * 5 = 5x + 50

After the distance traveled by each of A and B, they are still 170 miles apart

Hence, distance covered after 5 hours ;

Total miles - miles left

1020 - 170 = 850 miles

Hence,

5x + 5x + 50 = 850

10x = 850 - 50

10x = 800

x = 80

Train A = 80 miles per hour

Train B = 80 + 10 = 90 miles per hour

5 0

3 years ago

Gus has a lunch food budget of $190 per month. He spends an average of $5 per day on lunch. Which of the following equations rep

olganol [36]

Answer:

The answer is C.

Step-by-step explanation:

Each day (x) he loses 5 dollars from his total of 190. And C shows that because 190 - 5 x. 190 is his total, 5 is dollars lost a day, and x is days

3 0

3 years ago

(-17) x (-46) =<br> find the product

alina1380 [7]

Answer:

782

Step-by-step explanation:

Hope this helps

4 0

3 years ago

A job can be done by 30 men in 15 days. How long would it take 10 men to do the same job?

Vladimir79 [104]

Answer:

5 days

Step-by-step explanation:

This questions involves ratios, the job with 30 men can be done in 15 days, so the ratio from amount of men to amount of days the job will take to complete, it is 30:15. If we had 10 men instead of 30, 10 is one-third of 30, so you have to divide by 3 on each side of the ratio to get your answer.

If we do that we get the ratio 10:5.

Meaning that the 5 is the amount of days needed to be taken in order the complete the job.

Hope this helps!

3 0

3 years ago

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

6 0

2 years ago