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UkoKoshka [18]
3 years ago
13

Find the slope of the line going through the points 2, -3 and -1, 15

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

18/-3

Step-by-step explanation:

first you have to remember that slope is in rise over run format. knowing this figure how mush is in-between the y numbers. in this equation it is 28 between the y and -3 between 2 to -1

Evgen [1.6K]3 years ago
7 0

Answer:

<h2>-6</h2>

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (2, -3) and (-1, 15).

Substitute:

m=\dfrac{15-(-3)}{-1-2}=\dfrac{15+3}{-3}=\dfrac{18}{-3}=-6

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A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of
Troyanec [42]

Answer:

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Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

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x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

m=\frac{y2-y1}{x2-x1}

m=2

so

2=\frac{y2-y1}{x2-x1}  -----> equation A

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substitute equation B in equation A

2=\frac{y2-y1}{x1+3.5-x1}  

2=\frac{y2-y1}{3.5}  

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For the rotation - 660°, find the coterminal angle from 0° &lt; 0 &lt; 360°, thequadrant and the reference angle.
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Given the angle:

-660°

Let's find the coterminal angle from 0≤θ≤360.

To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,

We have:

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Therefore, the coterminal angle is 60°.

Since 60 degrees is between 0 to 90 degrees, is is quadrant I.

60 degrees lie in Quadrant I.

Also since it is in quadrant I, the reference angle is still 60 degrees.

ANSWER:

The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°

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