A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of
1 answer:
Answer:
The ordinate of B exceeds the ordinate of A by 7
Step-by-step explanation:
Let
A(x1,y1),B(x2,y2)
where
x1 is the abscissa of A
x2 is the abscissa of B
y1 is the ordinate of A
y2 is the ordinate of B
we know that
so
-----> equation A
----> equation B
substitute equation B in equation A
therefore
The ordinate of B exceeds the ordinate of A by 7
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The asymptotes of the reciprocal function are x = 3 and y = 4. Also, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
<h3>How to determine the values of a, c, d and k?</h3>The function is given as:
f(x) = -2[1/0.5(x -3)] + 4
A reciprocal function is generally represented as:
f(x) = a[1/(x -c)] + k
So, we have:
a = -2
c = -3 * 0.5
c = -1.5
k = 4
d = 0
Hence, the values of a, c, d and k are -2, -1.5, 0 and 4
<h3>The asymptotes</h3>We have:
f(x) = -2[1/0.5(x -3)] + 4
Set the radical to 0
y = 0 + 4
Evaluate
y = 4
Set the denominator to 0
x - 3 = 0
Evaluate
x = 3
Hence, the asymptotes are x = 3 and y = 4
<h3>The graph of the function</h3>See attachment for the graph of the function f(x) = -2[1/0.5(x -3)] + 4
The table of values is
x y
-4 4.6
-2 4.8
2 8
4 0
From the graph of the function, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
Read more about functions at:
#SPJ1
Answer:
Step-by-step explanation:
a²+b²=c² so: 33²+15²=x²
1089+225=x²
1314=x²
take the square root of both sides
36.249=x or
=x