Question

A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of the ordinate of B to the ordinate of A.

Answer 1

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

so

$2=\frac{y2-y1}{x2-x1}$  -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$  

$2=\frac{y2-y1}{3.5}$  

$7=y2-y1$  

$y2=y1+7$  

therefore

The ordinate of B exceeds the ordinate of A by 7